несовсем, нужно розпарсить одну тока строку в таком формате.
полазив по исходникам файлов, я нашел отличный парсер (мод. вариант):
| Код |
private static String[] parseLine(String nextLine) throws IOException {
char quotechar = '"';
char separator = ',';
if (nextLine == null) {
return null;
}
ArrayList tokensOnThisLine = new ArrayList();
StringBuffer sb = new StringBuffer();
boolean inQuotes = false;
do {
if (inQuotes) {
// continuing a quoted section, reappend newline
sb.append("\n");
nextLine = null;
if (nextLine == null)
break;
}
for (int i = 0; i < nextLine.length(); i++) {
char c = nextLine.charAt(i);
if (c == quotechar) {
// this gets complex... the quote may end a quoted block, or escape another quote.
// do a 1-char lookahead:
if( inQuotes // we are in quotes, therefore there can be escaped quotes in here.
&& nextLine.length() > (i+1) // there is indeed another character to check.
&& nextLine.charAt(i+1) == quotechar ){ // ..and that char. is a quote also.
// we have two quote chars in a row == one quote char, so consume them both and
// put one on the token. we do *not* exit the quoted text.
sb.append(nextLine.charAt(i+1));
i++;
}else{
inQuotes = !inQuotes;
// the tricky case of an embedded quote in the middle: a,bc"d"ef,g
if(i>2 //not on the begining of the line
&& nextLine.charAt(i-1) != separator //not at the begining of an escape sequence
&& nextLine.length()>(i+1) &&
nextLine.charAt(i+1) != separator //not at the end of an escape sequence
){
sb.append(c);
}
}
} else if (c == separator && !inQuotes) {
tokensOnThisLine.add(sb.toString());
sb = new StringBuffer(); // start work on next token
} else {
sb.append(c);
}
}
} while (inQuotes);
tokensOnThisLine.add(sb.toString());
return (String[]) tokensOnThisLine.toArray(new String[0]);
}
|
оригинал был взят с http://opencsv.svn.sourceforge.net/viewvc/opencsv/trunk/src/au/com/bytecode/opencsv/CSVReader.java?revision=15&view=markup
так что тема закрыта, спасиба |