Добрый день.
Решил изучить spring и попробовать сделать небольшое тестовое приложение.
Есть 2 сервиса, которые содержат друг друга и которые мне надо вытянуть из контекста спринга.
AuditoriumServiceImpl.java:
| Код |
public class AuditoriumServiceImpl extends GenericServiceImpl<Auditorium> implements IAuditoriumService{
private IBuildingService buildingService;
public AuditoriumServiceImpl() {
super(Auditorium.class);
}
public void setBuildingService(IBuildingService buildingService) {
this.buildingService = buildingService;
}
public IBuildingService getBuildingService() {
return buildingService;
}
}
|
BuildingServiceImpl.java
| Код |
public class BuildingServiceImpl extends GenericServiceImpl<Building> implements IBuildingService {
private IAuditoriumService auditoriumService;
public BuildingServiceImpl(){
super(Building.class);
}
public void setAuditoriumService(IAuditoriumService auditoriumService) {
this.auditoriumService = auditoriumService;
}
public IAuditoriumService getAuditoriumService() {
return auditoriumService;
}
}
|
spring-context.xml
| Код |
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-2.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-2.0.xsd">
<bean id="emf" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="persistenceUnit" />
</bean>
<bean id="jpaTemplate" class="org.springframework.orm.jpa.JpaTemplate">
<property name="entityManagerFactory" ref="emf" />
</bean>
<bean name="buildingService" class="com.pk.service.impl.BuildingServiceImpl">
<property name="jpaTemplate" ref="jpaTemplate" />
<property name="auditoriumService" ref="auditoriumService"></property>
</bean>
<bean name="auditoriumService" class="com.pk.service.impl.AuditoriumServiceImpl">
<property name="jpaTemplate" ref="jpaTemplate" />
<property name="buildingService" ref="buildingService" />
</bean>
</beans>
|
При вызове
| Код |
ApplicationContext applicationContext = new ClassPathXmlApplicationContext("/spring-context.xml");
IBuildingService serv = (IBuildingService) applicationContext.getBean("buildingService");
|
выдает следующее исключение:
| Код |
org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'buildingService': Bean with name 'buildingService' has been injected into other beans [auditoriumService] in its raw version as part of a circular reference, but has eventually been wrapped (for example as part of auto-proxy creation). This means that said other beans do not use the final version of the bean. This is often the result of over-eager type matching - consider using 'getBeanNamesOfType' with the 'allowEagerInit' flag turned off, for example.
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:464)
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:383)
java.security.AccessController.doPrivileged(Native Method)
|
В нете читал что данный эксепшен возникает из-за циклической зависимости бинов, созданных через конструкторы.
Я же использую сеттеры. возможно я что-то недопонял, с английским у меня не ахти...
Заранее спасибо. |