Цитата(wir @ 15.12.2009, 18:25  ) | | скалярное произведение=а*b*cos угла между а и b |
тогда уж a*b = |а|*|b|*cos угла между а и b
возвращаю cos = a*b/(|а|*|b|), а то непонятно.
| Код |
#include <iostream>
#include <cmath>
using namespace std;
class Vector
{
private:
double a,b,c,d,e;
public:
Vector(){}
Vector(double x,double y, double z, double q, double w)
{
a=x; b=y; c=x; d=q; e=w;
}
Vector(Vector &k)
{
a=k.a; b=k.b; c=k.c; d=k.d; e=k.e;
}
void Show()
{
cout << "(" << a << "," << b << "," << c << "," << d << "," << e << ")" << endl;
}
Vector operator+(Vector &);
friend Vector operator*(int, Vector&);
friend double operator*(Vector&, Vector&);
};
Vector Vector::operator+(Vector& k)
{
Vector temp;
temp.a = a + k.a;
temp.b = b + k.b;
temp.c = c + k.c;
temp.d = d + k.d;
temp.e = e + k.e;
return temp;
}
Vector operator*(int val, Vector& k)
{
k.a = val*k.a;
k.b = val*k.b;
k.c = val*k.c;
k.d = val*k.d;
k.e = val*k.e;
return k;
}
double operator*(Vector& A, Vector& B)
{
double ab = A.a*B.b + A.b*B.b + A.c*B.c + A.d*B.d + A.e*B.e;
double moda = sqrt(A.a*A.b + A.b*A.b + A.c*A.c + A.d*A.d + A.e*A.e);
double modb = sqrt(B.a*B.b + B.b*B.b + B.c*B.c + B.d*B.d + B.e*B.e);
double cosin = ab/(moda*modb);
return cosin;
}
int main()
{
Vector v1(1,-2.1,1,1,1),v2(1,1,1,1,1),v3;
v3 = v1 + v2; // сумма векторов
double x = v1*v2;
cout << x << endl;
system("pause");
return 0;
}
|
|