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Форум программистов > WPF и Silverlight > не работает выравнивание в ListView

Автор: Stas123 29.11.2011, 14:41

Такой код не делает выравнивания по правому краю в столбцах. Как быть? Код <ListView  HorizontalContentAlignment="Right" Background="Gainsboro" ItemsSource="{Binding ElementName=peoplesWindow, Path=Data}" >                     <ListView.View >                         <GridView >                             <GridViewColumn Width="80" Header="Name"  DisplayMemberBinding="{Binding Path=Name}" />                         </GridView>                     </ListView.View>                 </ListView>

Автор: Imir 29.11.2011, 14:57

Можно использовать стили.  Например вот так: Код <ListView x:Name="PLn" HorizontalContentAlignment="Right" Background="Gainsboro" ItemsSource="{Binding ElementName=peoplesWindow, Path=Data}" >                                 <ListView.View >                                     <GridView>                                         <GridViewColumn Width="80" Header="Name"  DisplayMemberBinding="{Binding Path=Name}">                                             <GridViewColumn.HeaderContainerStyle>                                                 <Style TargetType="{x:Type GridViewColumnHeader}" BasedOn="{StaticResource {x:Type GridViewColumnHeader}}">                                                     <Setter Property="HorizontalContentAlignment"                                                                   Value="{Binding Path=HorizontalContentAlignment, RelativeSource={RelativeSource AncestorType={x:Type ListView}}}"/>                                                 </Style>                                             </GridViewColumn.HeaderContainerStyle>                                         </GridViewColumn>                                     </GridView>                                 </ListView.View>                             </ListView> Хотя конечно лучше вынести стили в ресурсы.

Автор: Stas123 29.11.2011, 17:24

Imir, Спасибо, но мне нужно выравнивать не заголовок столбца, а содержимое столбца. Как это реализовать?

Автор: Imir 29.11.2011, 18:45

Тогда можно вот так: Код  <ListView HorizontalContentAlignment="Right" Background="Gainsboro" IsTextSearchCaseSensitive="True"                   ItemsSource="{Binding ElementName=peoplesWindow, Path=Data}">                                 <ListView.View>                                     <GridView>                                         <GridViewColumn Width="80" Header="Name">                                             <GridViewColumn.HeaderContainerStyle>                                                 <Style TargetType="{x:Type GridViewColumnHeader}"                                                             BasedOn="{StaticResource {x:Type GridViewColumnHeader}}">                                                     <Setter Property="HorizontalContentAlignment"                                                                   Value="{Binding Path=HorizontalContentAlignment, RelativeSource={RelativeSource AncestorType={x:Type ListView}}}"/>                                                 </Style>                                             </GridViewColumn.HeaderContainerStyle>                                             <GridViewColumn.CellTemplate>                                                 <DataTemplate>                                                     <TextBlock Background="AntiqueWhite" HorizontalAlignment="Stretch" TextAlignment="Right" Text="{Binding Path=Name}"/>                                                 </DataTemplate>                                             </GridViewColumn.CellTemplate>                                         </GridViewColumn>                                     </GridView>                                 </ListView.View>                                 <ListView.ItemContainerStyle>                                     <Style TargetType="{x:Type ListViewItem}">                                         <Setter Property="HorizontalContentAlignment" Value="Stretch"/>                                     </Style>                                 </ListView.ItemContainerStyle>                             </ListView>

Автор: Stas123 30.11.2011, 16:12

Imir, спасибо, заработало.

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